In cats, the allele for short fur (F) is dominant over the allele for long fur (f).

Question

Complete the Punnett Square to represent the cross between a heterozygous short fur cat and a long furred cat.

Place only one label in each box.
You may use each label more than once.
You do not need to use all the labels.
There may be more than one correct answer.
(4 points)
Drop target 1
Drop target 2
Drop target 3
Drop target 4
Drop target 5
Drop target 6
Drop target 7
Drop target 8

Answer 1

To set up the Punnett Square for a cross between a heterozygous short fur cat (Ff) and a long fur cat (ff), we will represent the genotypes and fill in the boxes based on the possible offspring.

1. Parent Genotypes:

   • Parent 1: Ff (heterozygous short fur)
   • Parent 2: ff (homozygous long fur)

2. Gametes:

   • Parent 1 can produce gametes: F, f
   • Parent 2 can produce gametes: f, f

3. Punnett Square Layout:

          |    f    |    f    
------------------------
       F  |   Ff    |   Ff   
------------------------
       f  |   ff    |   ff   

Filling the Punnett Square:

• Top cells (from Parent 1):

  • First column: Cross F with f → Ff (short fur)
  • Second column: Cross F with f → Ff (short fur)

• Bottom cells (from Parent 2):

  • First column: Cross f with f → ff (long fur)
  • Second column: Cross f with f → ff (long fur)

4. Final Punnett Square:

          |    f    |    f    
------------------------
       F  |   Ff    |   Ff   
------------------------
       f  |   ff    |   ff   

Labels:

• You can label the boxes as “Ff” and “ff”.
• For example:
  • Drop target 1: Ff
  • Drop target 2: Ff
  • Drop target 3: ff
  • Drop target 4: ff

This completes the Punnett Square with an explanation of how to fill it out. The offspring's potential genotypes are: 50% Ff (short fur) and 50% ff (long fur).