Tyrese wants to build a three-dimensional structure for a project. He needs to choose from a cube, rectangular prism, triangular prism, or square pyramid. He knows that whatever he chooses will impact what his friend, Miguel, will need to build. If you were Tyrese, what structure would you build?

Once he chooses his structure, he needs to sketch the figure and label the whole number dimensions needed to find the surface area of the figure. His friend, Miguel, needs to build the same figure, but needs to double all of the dimensions.

Write an explanation of what happens to the surface area of the figures when the dimensions are doubled. Include all relevant math work to help clarify your explanation.

1 answer

If I were Tyrese, I would choose to build a rectangular prism for my three-dimensional project. The rectangular prism is versatile and allows for a variety of dimensions, which can make it visually interesting and provide a solid base for construction.

Sketch and Dimensions

Let's say I choose a rectangular prism with the following dimensions:

  • Length (L) = 4 units
  • Width (W) = 3 units
  • Height (H) = 5 units

I would sketch the rectangular prism and label these dimensions clearly.

Surface Area Calculation

The formula for calculating the surface area (SA) of a rectangular prism is: \[ SA = 2(LW + LH + WH) \]

Plugging in the values: \[ SA = 2(4 \cdot 3 + 4 \cdot 5 + 3 \cdot 5) \] \[ SA = 2(12 + 20 + 15) \] \[ SA = 2(47) \] \[ SA = 94 \text{ square units} \]

Miguel's Construction

Miguel will need to double all of the dimensions of the rectangular prism:

  • New Length (L) = 4 * 2 = 8 units
  • New Width (W) = 3 * 2 = 6 units
  • New Height (H) = 5 * 2 = 10 units

New Surface Area Calculation

Now, we can calculate the surface area of Miguel's rectangular prism using the same formula: \[ SA = 2(LW + LH + WH) \] For Miguel’s dimensions: \[ SA = 2(8 \cdot 6 + 8 \cdot 10 + 6 \cdot 10) \] \[ SA = 2(48 + 80 + 60) \] \[ SA = 2(188) \] \[ SA = 376 \text{ square units} \]

Understanding the Change in Surface Area

When we compare the surface areas:

  • Tyrese's surface area = 94 square units
  • Miguel's surface area = 376 square units

It can be observed that Miguel's surface area is 4 times that of Tyrese’s: \[ \frac{376}{94} = 4 \]

Explanation

When the dimensions of a three-dimensional shape (like our rectangular prism) are doubled, the surface area doesn’t just double—it increases by a factor of four. This occurs because surface area is dependent on the square of the linear dimensions. Specifically, if the dimensions are scaled by a factor of k (in this case, k=2), the surface area scales by a factor of \( k^2 \): \[ SA_{\text{new}} = k^2 \cdot SA_{\text{original}} \] Thus, \( 2^2 = 4 \), which explains why Miguel’s rectangular prism has a surface area 4 times larger than Tyrese's.

This demonstrates the powerful effect that scaling dimensions has on surface area in three-dimensional geometry.