Which of the following correctly changes log25200

to an equivalent expression?(1 point)
Responses

log200log25
Start Fraction logarithm 200 over logarithm 25 End Fraction

log25log200
Start Fraction logarithm 25 over logarithm 200 End Fraction

log200log525
Start Fraction logarithm 200 over logarithm subscript 5 baseline 25 End Fraction

log200ln25

1 answer

To convert \( \log_{25} 200 \) to an equivalent expression using the change of base formula, we use the formula:

\[ \log_{a} b = \frac{\log_{c} b}{\log_{c} a} \]

For \( \log_{25} 200 \), we can choose any base \( c \), but a common choice is base 10 (logarithm) or the natural logarithm (ln).

Applying the change of base formula gives:

\[ \log_{25} 200 = \frac{\log 200}{\log 25} \]

or

\[ \log_{25} 200 = \frac{\ln 200}{\ln 25} \]

Looking at the provided responses:

  1. \( \frac{\log 200}{\log 25} \) - This is correct.
  2. \( \frac{\log 25}{\log 200} \) - This is incorrect (the order is reversed).
  3. \( \frac{\log 200}{\log_5 25} \) - This isn't necessarily equivalent without further calculation, as it uses a different base.
  4. \( \log_{200} \ln 25 \) - This is incorrect.

Therefore, the correct equivalent expression is:

\[ \frac{\log 200}{\log 25} \]