Here are the answers to your questions one by one:
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Only friction between the air and the satellite piece prevents the formula from the conservation of energy from being completely accurate. This is stated as mechanical energy loss.
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The equation that describes the energy conversions in the motion of a roller coaster car dropping down a hill is KEi + PEi = KEf + PEf.
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The mechanic applied torque calculated by the formula τ = r * F, where r = 0.6 m and F = weight in Newtons. The weight can be calculated as F = m * g = 100 kg * 9.8 m/s² = 980 N. Therefore, Torque = 0.6 m * 980 N = 588 N-m.
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The mechanical energy of the falling satellite piece is the sum of its kinetic and potential energy: Mechanical Energy = KE + PE = 47 J + 198 J = 245 J.
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Since the satellite pieces were orbiting the earth from a height of 50 miles, they had potential energy, or energy due to their position.
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A(n) watt or horsepower may be used to express power.
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To find the work done by the waitress, use the formula: Work = Force × Distance. Work = 3.2 N × 4.6 m = 14.72 J.
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The little girl performed work.
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The potential energies of the satellite pieces were converted to kinetic energy, or energy that objects possess due to motion.
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The pieces hit the earth with the force of their mechanical energy or their potential energy combined with their kinetic energy.
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The mechanical energy of a moving object can be calculated by the following formula: ME = KE + PE.
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The potential energy can be expressed by the formula: PE = mgh.
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Work is measured in joules.
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The piece with a mass of 213 kg would have greater potential energy since potential energy is directly proportional to mass.
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Power can be calculated using the formula Power = Work / Time. From question #7, Work = 14.72 J. Time = 2 minutes = 120 seconds. Thus, Power = 14.72 J / 120 s = 0.1223 W (or approximately 0.12 W).
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If we measured the rate work is accomplished, we would be measuring power.
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The amount of work necessary to move an object can be expressed in joules.
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The potential energy due to gravity for the satellite piece with a mass of 213 kg, at the height near Earth's surface (assuming g = 9.8 m/s²), would be PE = mgh. However, if it is already on the Earth's surface, PE would be 0 J.
Please let me know if you need any further clarification!