The radius of a circle is 6 in. Find the area of a sector with an angle of 120°.(1 point)

Responses

A=12π in.2
upper A equals 12 pi in. squared

A=2π in.2
upper A equals 2 pi in. squared

A=9π in.2
upper A equals 9 pi in. squared

A=36π in.2

1 answer

To find the area of a sector of a circle, you can use the formula:

\[ A = \frac{\theta}{360} \times \pi r^2 \]

where \( A \) is the area of the sector, \( \theta \) is the angle of the sector in degrees, and \( r \) is the radius of the circle.

In this case:

  • The radius \( r = 6 \) in.
  • The angle \( \theta = 120^\circ \).

Now plug the values into the formula:

\[ A = \frac{120}{360} \times \pi (6)^2 \]

Calculating this step by step:

  1. Calculate \( \frac{120}{360} = \frac{1}{3} \).
  2. Calculate \( (6)^2 = 36 \).
  3. Now substitute these values back into the formula:

\[ A = \frac{1}{3} \times \pi \times 36 \]

  1. Simplify:

\[ A = \frac{36\pi}{3} = 12\pi \]

Thus, the area of the sector is:

\[ \boxed{12\pi \text{ in}^2} \]