Question
USE SMALL WORDS Use this reaction to answer the question.
CH3COOH → CO2 + CH4
Use the table of molar masses to complete the activity.
Element Molar Mass (g/mol)
carbon 12.01
hydrogen 1.01
oxygen 16.00
A chemist will use a sample of 30 g of ethanol (CH3CH2OH) in an experiment. In 1–2 sentences, make and justify a claim about the number of moles of ethanol the chemist will use by calculating the molar mass of ethanol and using it to find moles.
(2 points)
CH3COOH → CO2 + CH4
Use the table of molar masses to complete the activity.
Element Molar Mass (g/mol)
carbon 12.01
hydrogen 1.01
oxygen 16.00
A chemist will use a sample of 30 g of ethanol (CH3CH2OH) in an experiment. In 1–2 sentences, make and justify a claim about the number of moles of ethanol the chemist will use by calculating the molar mass of ethanol and using it to find moles.
(2 points)
Answers
Answered by
GPT-4o mini
To find the number of moles of ethanol (C2H5OH), we first need to calculate its molar mass. The molar mass of ethanol is:
- Carbon: 2 x 12.01 g/mol = 24.02 g/mol
- Hydrogen: 6 x 1.01 g/mol = 6.06 g/mol
- Oxygen: 1 x 16.00 g/mol = 16.00 g/mol
Adding these together:
24.02 + 6.06 + 16.00 = 46.08 g/mol
Now, to find the number of moles in 30 g of ethanol:
Moles = mass (g) / molar mass (g/mol) = 30 g / 46.08 g/mol ≈ 0.65 moles
**Claim:** The chemist will use about 0.65 moles of ethanol. This is based on the molar mass of ethanol being 46.08 g/mol, allowing us to calculate how many moles are in the 30 g sample.
- Carbon: 2 x 12.01 g/mol = 24.02 g/mol
- Hydrogen: 6 x 1.01 g/mol = 6.06 g/mol
- Oxygen: 1 x 16.00 g/mol = 16.00 g/mol
Adding these together:
24.02 + 6.06 + 16.00 = 46.08 g/mol
Now, to find the number of moles in 30 g of ethanol:
Moles = mass (g) / molar mass (g/mol) = 30 g / 46.08 g/mol ≈ 0.65 moles
**Claim:** The chemist will use about 0.65 moles of ethanol. This is based on the molar mass of ethanol being 46.08 g/mol, allowing us to calculate how many moles are in the 30 g sample.
There are no human answers yet. A form for humans to post answers is coming very soon!