Question
Al2O3 A1 +O2
Answers
GPT-4o mini
To balance the reaction involving aluminum oxide (Al₂O₃) and oxygen (O₂), we need to determine the correct stoichiometry for how aluminum (Al) and oxygen combine to form aluminum oxide.
The unbalanced reaction can be written as:
\[ \text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3 \]
To balance the equation, we follow these steps:
1. **Count the number of atoms of each element on both sides**:
- On the left, we have aluminum (Al) and oxygen (O): Al = 1 (for each Al), O = 2 (from O₂).
- On the right, in Al₂O₃: Al = 2, O = 3.
2. **Balance the aluminum atoms** first. Since there are 2 aluminum atoms in Al₂O₃, we need 2 Al on the left:
\[ 2 \text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3 \]
3. **Balance the oxygen atoms** next. We have 3 oxygen atoms on the right in Al₂O₃ and only 2 oxygen atoms from O₂ on the left. To balance the oxygen, we can use 3/2 of O₂, but it's more conventional to use whole numbers. Thus, we can multiply the entire equation by 2 to eliminate the fraction:
\[ 4 \text{Al} + 3 \text{O}_2 \rightarrow 2 \text{Al}_2\text{O}_3 \]
So the balanced chemical equation for the formation of aluminum oxide from aluminum and oxygen is:
\[ 4 \text{Al} + 3 \text{O}_2 \rightarrow 2 \text{Al}_2\text{O}_3 \]
The unbalanced reaction can be written as:
\[ \text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3 \]
To balance the equation, we follow these steps:
1. **Count the number of atoms of each element on both sides**:
- On the left, we have aluminum (Al) and oxygen (O): Al = 1 (for each Al), O = 2 (from O₂).
- On the right, in Al₂O₃: Al = 2, O = 3.
2. **Balance the aluminum atoms** first. Since there are 2 aluminum atoms in Al₂O₃, we need 2 Al on the left:
\[ 2 \text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3 \]
3. **Balance the oxygen atoms** next. We have 3 oxygen atoms on the right in Al₂O₃ and only 2 oxygen atoms from O₂ on the left. To balance the oxygen, we can use 3/2 of O₂, but it's more conventional to use whole numbers. Thus, we can multiply the entire equation by 2 to eliminate the fraction:
\[ 4 \text{Al} + 3 \text{O}_2 \rightarrow 2 \text{Al}_2\text{O}_3 \]
So the balanced chemical equation for the formation of aluminum oxide from aluminum and oxygen is:
\[ 4 \text{Al} + 3 \text{O}_2 \rightarrow 2 \text{Al}_2\text{O}_3 \]