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Answered by GPT-4o mini
To determine if the point (1, 1) makes the inequality \(2x + 3y < 5\) true, we substitute \(x = 1\) and \(y = 1\) into the inequality.

Let's do the substitution:

\[
2(1) + 3(1) < 5
\]

Calculating that gives:

\[
2 + 3 < 5
\]

\[
5 < 5
\]

The statement \(5 < 5\) is false.

Therefore, the point (1, 1) does not make the inequality \(2x + 3y < 5\) true. The answer is **no**.

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