Asked by Catherine
how do i get rid of the fractions in this expression ? its supposed to be using order of operations
original problem:
(6^2 + 18) divided by 9 + 2/3(8)-6
original problem:
(6^2 + 18) divided by 9 + 2/3(8)-6
Answers
Answered by
MathMate
To provide help, we must know exactly what the question is.
The given expression can be interpreted in many ways, depending on whether parentheses are missing.
If no parentheses are missing, it is interpreted as:
((6^2 + 18)/9) + ((2/3)*(8)) - 6
Does the interpreted expression represent the question correctly?
Remember that the fractions in text-books are expressed using typography which has to be replaced by properly inserting parentheses. Numerators and denominators containing more than one term have to be enclosed in parentheses.
The given expression can be interpreted in many ways, depending on whether parentheses are missing.
If no parentheses are missing, it is interpreted as:
((6^2 + 18)/9) + ((2/3)*(8)) - 6
Does the interpreted expression represent the question correctly?
Remember that the fractions in text-books are expressed using typography which has to be replaced by properly inserting parentheses. Numerators and denominators containing more than one term have to be enclosed in parentheses.
Answered by
Catherine
yes that's represents the question correctly, but how do i get rid of the fractions?
Answered by
Reiny
(6^2 + 18) divided by 9 + 2/3(8)-6
= 54/9 + 16/3 - 6
= 6 + 16 - 6
= 16/3 or 5 1/3
http://www.google.com/search?rls=ig&hl=en&source=hp&q=%286%5E2+%2B+18%29%2F9+%2B+2%2F3%288%29-6+&btnG=Google+Search&aq=f&aqi=&aql=&oq=&gs_rfai=
= 54/9 + 16/3 - 6
= 6 + 16 - 6
= 16/3 or 5 1/3
http://www.google.com/search?rls=ig&hl=en&source=hp&q=%286%5E2+%2B+18%29%2F9+%2B+2%2F3%288%29-6+&btnG=Google+Search&aq=f&aqi=&aql=&oq=&gs_rfai=
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