Use the following formula to find the efficiency of energy transfer between the harbor seal (2,500 Kcal) and a polar bear (375 Kcal).

Question

(Energy level transfered to next level)(Total energy input) × 100

(1 point)
Responses

12%
12%
15%
15%
10%
10%
20%

Answer 1

To calculate the efficiency of energy transfer between the harbor seal and the polar bear using the given formula, we will use the values provided:

• Energy transferred to the polar bear (from the harbor seal): 375 Kcal
• Total energy input from the harbor seal: 2,500 Kcal

Now, we can plug these values into the formula:

\[ \text{Efficiency} = \left( \frac{\text{Energy level transferred to next level}}{\text{Total energy input}} \right) \times 100 \]

\[ \text{Efficiency} = \left( \frac{375}{2500} \right) \times 100 \]

Calculating this:

\[ \frac{375}{2500} = 0.15 \]

Now, multiply by 100 to convert it to a percentage:

\[ 0.15 \times 100 = 15% \]

Thus, the efficiency of energy transfer between the harbor seal and the polar bear is 15%.