To solve the system of equations given by:
- \( y = -4x - 2 \)
- \( y = \frac{1}{2}x - 2 \)
we can set the two equations equal to each other since they both equal \( y \):
\[ -4x - 2 = \frac{1}{2}x - 2 \]
Now, let's solve for \( x \):
- Add 2 to both sides:
\[ -4x = \frac{1}{2}x \]
- To eliminate the fraction, let's multiply every term by 2:
\[ -8x = x \]
- Now, add \( 8x \) to both sides:
\[ 0 = 9x \]
- Divide by 9:
\[ x = 0 \]
Now that we have \( x \), we can substitute it back into either equation to find \( y \). Using the second equation:
\[ y = \frac{1}{2}(0) - 2 = -2 \]
Thus, the solution to the system of equations is:
\[ (x, y) = (0, -2) \]
To summarize, the solution to the system of equations is \( (0, -2) \).