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Triangle MNO

is translated up 5 units and left 2 units. Point N
is located at (0, −6)
. What are the coordinates of N′
?

1 answer

To find the new coordinates \( N' \) of point \( N \) after translating it up 5 units and left 2 units, we start with the original coordinates of point \( N \), which are \( (0, -6) \).

  1. Translate Up 5 Units: This means we add 5 to the y-coordinate. \[ -6 + 5 = -1 \] So, after moving up 5 units, the coordinates are \( (0, -1) \).

  2. Translate Left 2 Units: This means we subtract 2 from the x-coordinate. \[ 0 - 2 = -2 \] So, after moving left 2 units, the coordinates become \( (-2, -1) \).

Thus, the coordinates of \( N' \) are \( \boxed{(-2, -1)} \).