To determine the correct similarity statement, we need to analyze the corresponding angles in both triangles.
The angles of the first triangle \( ABC \) are:
- \( m\angle A = 48^\circ \)
- \( m\angle B = 17^\circ \)
- \( m\angle C = 115^\circ \)
The angles of the second triangle \( HIJ \) are:
- \( m\angle H = 17^\circ \)
- \( m\angle I = 48^\circ \)
- \( m\angle J = 115^\circ \)
Now, we can match the angles:
- \( m\angle A \) in triangle \( ABC \) corresponds to \( m\angle I \) in triangle \( HIJ \).
- \( m\angle B \) in triangle \( ABC \) corresponds to \( m\angle H \) in triangle \( HIJ \).
- \( m\angle C \) in triangle \( ABC \) corresponds to \( m\angle J \) in triangle \( HIJ \).
Thus, the corresponding angles are:
- \( A \leftrightarrow I \)
- \( B \leftrightarrow H \)
- \( C \leftrightarrow J \)
This means that the triangles \( ABC \) and \( HIJ \) are similar, respecting the order of their corresponding angles as:
- \( \angle A \) corresponds to \( \angle I \)
- \( \angle B \) corresponds to \( \angle H \)
- \( \angle C \) corresponds to \( \angle J \)
Thus, the correct similarity statement is:
\[ \triangle ABC \sim \triangle HIJ \]
So the answer is:
△ABC∼△HIJ