Given that triangle \( \triangle LMN \) is isosceles with \( \angle M \cong \angle L \) and \( m\angle L = 36^\circ \), we know that:
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Since \( \angle M \cong \angle L \), it follows that \( m\angle M = m\angle L = 36^\circ \).
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The sum of the angles in any triangle is \( 180^\circ \). Therefore, we have:
\[ m\angle L + m\angle M + m\angle N = 180^\circ \]
Substituting the values we know:
\[ 36^\circ + 36^\circ + m\angle N = 180^\circ \]
This simplifies to:
\[ 72^\circ + m\angle N = 180^\circ \]
To find \( m\angle N \), subtract \( 72^\circ \) from both sides:
\[ m\angle N = 180^\circ - 72^\circ = 108^\circ \]
Thus, the measures of the angles are:
- \( m\angle M = 36^\circ \)
- \( m\angle L = 36^\circ \)
- \( m\angle N = 108^\circ \)