Question
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Part 1
Solve the following quadratic equation by factoring.
x squared minus x equals 6
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Part 1
The solution set is StartSet nothing EndSet .
(Simplify your answer. Use a comma to separate answers as needed.)
Part 1
Solve the following quadratic equation by factoring.
x squared minus x equals 6
Question content area bottom
Part 1
The solution set is StartSet nothing EndSet .
(Simplify your answer. Use a comma to separate answers as needed.)
Answers
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Answered by
GPT-4o mini
To solve the quadratic equation \( x^2 - x = 6 \) by factoring, we first rearrange the equation to set it to zero:
\[
x^2 - x - 6 = 0
\]
Next, we need to factor the quadratic expression \( x^2 - x - 6 \). We look for two numbers that multiply to \(-6\) (the constant term) and add to \(-1\) (the coefficient of \(x\)).
The numbers that satisfy these conditions are \(-3\) and \(2\) because:
\[
-3 \cdot 2 = -6 \quad \text{and} \quad -3 + 2 = -1
\]
Now we can write the factored form of the equation:
\[
(x - 3)(x + 2) = 0
\]
Setting each factor to zero gives us the possible solutions:
1. \( x - 3 = 0 \) which implies \( x = 3 \)
2. \( x + 2 = 0 \) which implies \( x = -2 \)
Thus, the solution set is:
\[
\{ 3, -2 \}
\]
So, the final answer is:
\(\{ 3, -2 \}\)
\[
x^2 - x - 6 = 0
\]
Next, we need to factor the quadratic expression \( x^2 - x - 6 \). We look for two numbers that multiply to \(-6\) (the constant term) and add to \(-1\) (the coefficient of \(x\)).
The numbers that satisfy these conditions are \(-3\) and \(2\) because:
\[
-3 \cdot 2 = -6 \quad \text{and} \quad -3 + 2 = -1
\]
Now we can write the factored form of the equation:
\[
(x - 3)(x + 2) = 0
\]
Setting each factor to zero gives us the possible solutions:
1. \( x - 3 = 0 \) which implies \( x = 3 \)
2. \( x + 2 = 0 \) which implies \( x = -2 \)
Thus, the solution set is:
\[
\{ 3, -2 \}
\]
So, the final answer is:
\(\{ 3, -2 \}\)
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