Question
When solving left brace Start 2 By 1 Matrix 1st Row 1st Column 3 x minus 2 y equals 9 2nd Row 1st Column y equals 6 x minus 6 EndMatrix
by the substitution method, x equals one third
is obtained. Find the solution set.
Question content area bottom
Part 1
The solution set is StartSet nothing EndSet
.
(Use a comma to separate answers as needed. Type an ordered pair, using integers or fractions.)
by the substitution method, x equals one third
is obtained. Find the solution set.
Question content area bottom
Part 1
The solution set is StartSet nothing EndSet
.
(Use a comma to separate answers as needed. Type an ordered pair, using integers or fractions.)
Answers
GPT-4o mini
To solve the system of equations using the substitution method, we start with the given equations:
1. \(3x - 2y = 9\)
2. \(y = 6x - 6\)
You've obtained \(x = \frac{1}{3}\). Now we can find the corresponding \(y\) value using the second equation.
Substituting \(x = \frac{1}{3}\) into the second equation:
\[
y = 6\left(\frac{1}{3}\right) - 6
\]
\[
y = 2 - 6
\]
\[
y = -4
\]
Now that we have both \(x\) and \(y\), the solution is:
\[
\left( \frac{1}{3}, -4 \right)
\]
Thus, the solution set is:
\[
\left\{ \left( \frac{1}{3}, -4 \right) \right\}
\]
In ordered pair notation, this is:
\[
\left( \frac{1}{3}, -4 \right)
\]
1. \(3x - 2y = 9\)
2. \(y = 6x - 6\)
You've obtained \(x = \frac{1}{3}\). Now we can find the corresponding \(y\) value using the second equation.
Substituting \(x = \frac{1}{3}\) into the second equation:
\[
y = 6\left(\frac{1}{3}\right) - 6
\]
\[
y = 2 - 6
\]
\[
y = -4
\]
Now that we have both \(x\) and \(y\), the solution is:
\[
\left( \frac{1}{3}, -4 \right)
\]
Thus, the solution set is:
\[
\left\{ \left( \frac{1}{3}, -4 \right) \right\}
\]
In ordered pair notation, this is:
\[
\left( \frac{1}{3}, -4 \right)
\]