Question

A box contain 4/5kg brown rice 3/10kg barely and 1/10kg black beans
How much more brown rice than black beans
And total mass

Answer 1

To determine how much more brown rice there is than black beans, we need to compare the two quantities.

The amount of brown rice is \( \frac{4}{5} \) kg, and the amount of black beans is \( \frac{1}{10} \) kg.

First, let's convert \( \frac{4}{5} \) kg into a fraction with a denominator of 10 for easy comparison:

\[
\frac{4}{5} = \frac{4 \times 2}{5 \times 2} = \frac{8}{10} \text{ kg}
\]

Now we can find the difference between the amounts of brown rice and black beans:

\[
\frac{8}{10} \text{ kg (brown rice)} - \frac{1}{10} \text{ kg (black beans)} = \frac{8 - 1}{10} = \frac{7}{10} \text{ kg}
\]

So, there is \( \frac{7}{10} \) kg more brown rice than black beans.

To find the total mass of the contents of the box, we will add the amounts of brown rice, barley, and black beans:

\[
\text{Brown rice} = \frac{4}{5} \text{ kg}
\]
\[
\text{Barley} = \frac{3}{10} \text{ kg}
\]
\[
\text{Black beans} = \frac{1}{10} \text{ kg}
\]

Now, we need a common denominator to add these fractions. The least common multiple of the denominators 5 and 10 is 10.

Converting \( \frac{4}{5} \) to tenths:

\[
\frac{4}{5} = \frac{8}{10}
\]

Now we can add all the fractions:

\[
\text{Total mass} = \frac{8}{10} + \frac{3}{10} + \frac{1}{10} = \frac{8 + 3 + 1}{10} = \frac{12}{10} = 1.2 \text{ kg}
\]

Thus, the total mass of the contents of the box is 1.2 kg.

In summary:
- There is \( \frac{7}{10} \) kg more brown rice than black beans.
- The total mass of the contents is 1.2 kg.