Question

Question

Use the graph to answer the question below.

The graph shows number of rotifers on the y-axis from 0 to 4500, in increments of 500. The x-axis is labeled as days. The data is as follows. Day 0: number of rotifers alone and number of rotifers with water fleas, 0. Day 2: number of rotifers alone and number of rotifers with water fleas, 0. Day 4: number of rotifers alone and number of rotifers with water fleas, 300. Day 6: number of rotifers alone and number of rotifers with water fleas, 500. Day 8: number of rotifers alone and number of rotifers with water fleas, 800. Day 10: number of rotifers alone, 1700 and number of rotifers with water fleas, 1600. Day 12: number of rotifers alone, 3000 and number of rotifers with water fleas, 1500. Day 14: number of rotifers alone, 4000 and number of rotifers with water fleas, 1100. Day 16: number of rotifers alone, 4200 and number of rotifers with water fleas, 200. Day 18: number of rotifers alone, 4200 and number of rotifers with water fleas, 0.

Examine the graph. What is the flask’s carrying capacity for rotifers in the presence of water fleas?

(1 point)
Responses

4,200
4,200

3,000
3,000

0
0

1,800
1,800
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Answer 1

The carrying capacity of a population is the maximum number of individuals that an environment can sustain indefinitely without being degraded.

From the data provided, we can observe the number of rotifers with water fleas over the course of 18 days. The highest count recorded is 1,700 on Day 10. After that, the populations decline and eventually drop to 0 by Day 18.

Thus, the carrying capacity for rotifers in the presence of water fleas is closest to 1,700, but among the response options given:

• 4,200
• 3,000
• 0
• 1,800

The option 1,800 is the most reasonable answer since it is the only value close to the maximum observed count of rotifers with water fleas and suggests the effective limit for sustainability in that scenario.

So, the answer would be:

1,800