a 10 kg object experiences a horisontal force of 10N which cause it to accelerate at 5 m/s2, moving it a distance of 20 m, horizontally. How much work is done by the force? (please show your work)

1 answer

To calculate the work done by the force, we can use the formula for work:

\[ \text{Work} (W) = \text{Force} (F) \times \text{Distance} (d) \times \cos(\theta) \]

where:

  • \( W \) is the work done,
  • \( F \) is the force applied,
  • \( d \) is the distance over which the force is applied,
  • \( \theta \) is the angle between the force and the direction of motion.

In this case, we have:

  • \( F = 10 , \text{N} \) (the horizontal force applied),
  • \( d = 20 , \text{m} \) (the distance over which the force is applied),
  • Since the force is in the same direction as the motion, \( \theta = 0^\circ \).

Now, we can plug in the values:

\[ \cos(0^\circ) = 1 \] \[ W = 10 , \text{N} \times 20 , \text{m} \times 1 \] \[ W = 200 , \text{J} \]

Therefore, the work done by the force is 200 Joules.