To solve the equation \( 30 = -x^2 + 13x \), we first rearrange it into standard form:
\[ -x^2 + 13x - 30 = 0 \]
Next, we can multiply through by -1 to make the leading coefficient positive:
\[ x^2 - 13x + 30 = 0 \]
Now we need to factor the quadratic expression \( x^2 - 13x + 30 \). We look for two numbers that multiply to 30 (the constant term) and add up to -13 (the coefficient of \( x \)). The numbers -3 and -10 fit this requirement:
\[ (x - 3)(x - 10) = 0 \]
Now, we can find the solutions by setting each factor equal to zero:
- \( x - 3 = 0 \) ⟹ \( x = 3 \)
- \( x - 10 = 0 \) ⟹ \( x = 10 \)
Thus, the solutions to the equation are:
\[ x = 3, , 10 \]
The correct answer from the options given is:
x=3,10 or x equals 3 comma 10.