Question

In a wall outlet with a resistance of 3.7 ohms and a voltage of 110V, what is the current flowing into the outlet?

(1 point)
Responses

113.7 A
113.7 A

0.04 A
0.04 A

29.7 A
29.7 A

407.0 A

Answer 1

To find the current flowing into the outlet, you can use Ohm's Law, which is defined as:

\[ I = \frac{V}{R} \]

where:
- \( I \) is the current in amperes (A),
- \( V \) is the voltage in volts (V),
- \( R \) is the resistance in ohms (Ω).

Given:
- Voltage \( V = 110 \) V,
- Resistance \( R = 3.7 \) Ω.

Substituting the values into the formula, we get:

\[ I = \frac{110 \, \text{V}}{3.7 \, \Omega} \]

Calculating this gives:

\[ I = \frac{110}{3.7} \approx 29.7 \, A \]

Therefore, the current flowing into the outlet is approximately **29.7 A**.