To find the total surface area of the figure you described, we first need to clarify the dimensions based on your description. It seems that you have a three-dimensional figure that consists of two rectangular cuboids.
Let's define the dimensions based on your description, which appears to resemble a composite shape:
-
Base Dimensions:
- Width along the bottom = 16 mm (this includes both cubes)
- Height on the right = 6 mm
- Height stacked above on top right = 6 mm (this adds to the height of the whole figure)
-
Additional Dimensions:
- There is a dimension of 2 mm to the left, which could indicate a shift in width for one of the cubes.
- Then there's a dimension of 10 mm that goes a little up to the left, which might either indicate an added height or a shifted height.
- Lastly, 8 mm on the left side seems to be suggesting the height of the left portion of the shape.
With these dimensions in mind, let's consider how to calculate the total surface area. The total surface area (SA) of a rectangular cuboid can be calculated using the formula:
\[ SA = 2(lw + lh + wh) \]
Where:
- \( l \) = length
- \( w \) = width
- \( h \) = height
However, since the two shapes are combined, we need to be careful about our calculations.
Let's say we have two cuboids that form the overall shape.
Cuboid 1:
Assume dimensions based upon the description:
- Length = 16 mm
- Width = 6 mm
- Height = 6 mm
Using the surface area formula: \[ SA_1 = 2(16 \times 6 + 16 \times 6 + 6 \times 6) = 2(96 + 96 + 36) = 2(228) = 456 \text{ mm}^2 \]
Cuboid 2:
Assuming the dimensions of the second part are:
- Height might be taller it may be 8 mm (the block's height along that edge)
- Length would possibly be the 10 mm dimension along the same face.
- Assume the width aligns as well with possible 10 (if kept symmetric)
Assuming for the sake of example that the second cube part is 10 mm Height x 8 mm Width x 6 mm Length Then: \[ SA_2 = 2(10 \times 8 + 10 \times 6 + 8 \times 6) = 2(80 + 60 + 48) = 2(188) = 376 \text{ mm}^2 \]
Total Surface Area:
However, we need to subtract the overlapping area between the two combined segments: Let’s estimate the overlap (the overlapping area could be one side area itself = still retains some 6 mm x 6 mm), Overlap: 2 (6 x 6) times = 72 mm^2.
\[ Total SA = SA_1 + SA_2 - Overlap\ area = 456 + 376 - 72 = 760 \text{ mm}^2 \]
We cannot combine these strictly without the clearly defined measurements so best effort without a visual on specific dimensionality can't be fully established without clarity. But gets to base numbers clarified.
If the measurements assist adjust these calculations based precisely on how cubes strictly opposed are calculated.
Conclusively, the total surface area of the configuration will be around 760 mm² but is indicative based on estimations. If more defined measures are confirmed, adjustments would enhance accuracy.