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Apply the Pythagorean Theorem to find the length between (−1, 6) and (5, −2) . Round your answer to the nearest hundredth, if n...
Apply the Pythagorean Theorem to find the length between (−1, 6) and (5, −2). Round your answer to the nearest hundredth, if necessary.(1 point)
Responses
14
14
9.22
9.22
10
10
100
Responses
14
14
9.22
9.22
10
10
100
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the length between the points \((-1, 6)\) and \( (5, -2)\), we use the distance formula, which is derived from the Pythagorean Theorem. The distance \(d\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Substituting the coordinates \((-1, 6)\) as \((x_1, y_1)\) and \((5, -2)\) as \((x_2, y_2)\):
- \(x_1 = -1\)
- \(y_1 = 6\)
- \(x_2 = 5\)
- \(y_2 = -2\)
Now we calculate the differences:
\[
x_2 - x_1 = 5 - (-1) = 6
\]
\[
y_2 - y_1 = -2 - 6 = -8
\]
Next, we can substitute these values into the distance formula:
\[
d = \sqrt{(6)^2 + (-8)^2}
\]
Calculating the squares:
\[
d = \sqrt{36 + 64}
\]
\[
d = \sqrt{100}
\]
\[
d = 10
\]
Therefore, the distance between the points \((-1, 6)\) and \( (5, -2)\) is \(10\).
The correct response is:
**10**
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Substituting the coordinates \((-1, 6)\) as \((x_1, y_1)\) and \((5, -2)\) as \((x_2, y_2)\):
- \(x_1 = -1\)
- \(y_1 = 6\)
- \(x_2 = 5\)
- \(y_2 = -2\)
Now we calculate the differences:
\[
x_2 - x_1 = 5 - (-1) = 6
\]
\[
y_2 - y_1 = -2 - 6 = -8
\]
Next, we can substitute these values into the distance formula:
\[
d = \sqrt{(6)^2 + (-8)^2}
\]
Calculating the squares:
\[
d = \sqrt{36 + 64}
\]
\[
d = \sqrt{100}
\]
\[
d = 10
\]
Therefore, the distance between the points \((-1, 6)\) and \( (5, -2)\) is \(10\).
The correct response is:
**10**
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