Question

A 50 gram piece of glass with the specific heat of 0.84 J/g°C is heated from 35°C to 46°C. How much heat is added to the glass?
*
1 point
11 J
193 J
462 J
1470 J

Answer 1

To calculate the amount of heat added to the glass, you can use the formula:

\[
Q = mc\Delta T
\]

where:
- \( Q \) is the heat added (in joules),
- \( m \) is the mass (in grams),
- \( c \) is the specific heat capacity (in J/g°C), and
- \( \Delta T \) is the change in temperature (in °C).

**Step 1: Identify the variables.**

- Mass \( m = 50 \) grams
- Specific heat \( c = 0.84 \) J/g°C
- Initial temperature \( T_i = 35 \)°C
- Final temperature \( T_f = 46 \)°C

**Step 2: Calculate the change in temperature \( \Delta T \).**

\[
\Delta T = T_f - T_i = 46°C - 35°C = 11°C
\]

**Step 3: Plug the values into the formula.**

\[
Q = mc\Delta T = 50 \, \text{g} \times 0.84 \, \text{J/g°C} \times 11 \, °C
\]

**Step 4: Perform the calculation.**

\[
Q = 50 \times 0.84 \times 11
\]

\[
Q = 50 \times 9.24 = 462 \, \text{J}
\]

Therefore, the amount of heat added to the glass is \( \boxed{462 \, \text{J}} \).