How many real solutions does the equation have?

u^2 = –64

1 answer

To find the number of real solutions for the equation \( u^2 = -64 \), we analyze the equation.

The left side, \( u^2 \), represents the square of a real number, which is always non-negative (i.e., \( u^2 \geq 0 \)). The right side of the equation is \(-64\), which is negative.

Since a non-negative number cannot equal a negative number, there are no real solutions to the equation \( u^2 = -64 \).

Thus, the answer is:

Zero real solutions.