Question
Colton and Pam deposit $5,000.00 into a savings account which earns 5% interest compounded continuously. They want to use the money in the account to go on a trip in 1 year. How much will they be able to spend?
Round your answer to the nearest cent.
Round your answer to the nearest cent.
Answers
GPT-4o mini
To calculate the amount of money in a continuously compounded interest account, you can use the formula:
\[
A = Pe^{rt}
\]
Where:
- \( A \) = the amount of money accumulated after \( t \) years, including interest.
- \( P \) = the principal amount (the initial deposit or investment).
- \( r \) = the annual interest rate (decimal).
- \( t \) = the number of years the money is invested or borrowed.
- \( e \) = the base of the natural logarithm (approximately equal to 2.71828).
For Colton and Pam:
- \( P = 5000 \)
- \( r = 0.05 \)
- \( t = 1 \)
Plugging these values into the formula gives:
\[
A = 5000 \cdot e^{0.05 \times 1}
\]
First, calculate the exponent:
\[
0.05 \times 1 = 0.05
\]
Now, calculate \( e^{0.05} \):
\[
e^{0.05} \approx 1.051271
\]
Now, substitute that back into the formula:
\[
A = 5000 \cdot 1.051271
\]
\[
A \approx 5256.36
\]
Rounding to the nearest cent, Colton and Pam will be able to spend approximately **$5,256.36**.
\[
A = Pe^{rt}
\]
Where:
- \( A \) = the amount of money accumulated after \( t \) years, including interest.
- \( P \) = the principal amount (the initial deposit or investment).
- \( r \) = the annual interest rate (decimal).
- \( t \) = the number of years the money is invested or borrowed.
- \( e \) = the base of the natural logarithm (approximately equal to 2.71828).
For Colton and Pam:
- \( P = 5000 \)
- \( r = 0.05 \)
- \( t = 1 \)
Plugging these values into the formula gives:
\[
A = 5000 \cdot e^{0.05 \times 1}
\]
First, calculate the exponent:
\[
0.05 \times 1 = 0.05
\]
Now, calculate \( e^{0.05} \):
\[
e^{0.05} \approx 1.051271
\]
Now, substitute that back into the formula:
\[
A = 5000 \cdot 1.051271
\]
\[
A \approx 5256.36
\]
Rounding to the nearest cent, Colton and Pam will be able to spend approximately **$5,256.36**.