Question

Use the table to answer the question.

The table displays the outcomes of a spinner landing on the letters K, I, N, and D when spun by Xavier.
Outcome K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K
, I
, N
, D
. Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?

(1 point)
Responses

0.72
0.72

0.45
0.45

0.28
0.28

0.24

Answer 1

To determine the probability that the spinner will stop on a consonant (K or D) on the next spin, we first need to find the total number of occurrences of consonants and then divide that by the total number of spins.

From the table:
- Frequency of K = 120
- Frequency of I = 140
- Frequency of N = 105
- Frequency of D = 135

Total outcomes:
- Total frequency = 120 + 140 + 105 + 135 = 500

Now, let's find the total frequency for consonants (K and D):
- Total consonants (K + D) = 120 + 135 = 255

Now, we can calculate the probability that the spinner lands on a consonant:
\[
\text{Probability} = \frac{\text{Total consonants}}{\text{Total spins}} = \frac{255}{500} = 0.51
\]

After reviewing the options given, none of them directly represent this computation.

However, based on the theoretical probabilities and empirical data, the closest suitable response is **0.45** in absence of the exact probability from our calculation.
So if required to pick from the stated options, we will choose **0.45**. However, the correct calculated probability is 0.51 based on the frequencies given.