The Punnett square for a non-freckled parent and a homozygous freckled parent is shown below. What is the probability that their children will have freckles?

Question

F F
f Ff Ff
f Ff Ff
A.
50%
B.
75%
C.
100%
D.
0%

Answer 1

To determine the probability of the children having freckles, we first need to understand the genotypes involved.

• The non-freckled parent has the genotype "ff" (no freckles).
• The homozygous freckled parent has the genotype "FF" (freckles).

In this case, the Punnett square will look like this:

       F      F
     ----------------
 f |   Ff   |   Ff   |
     ----------------
 f |   Ff   |   Ff   |
     ----------------

All offspring (Ff) have one dominant allele (F) for freckles and one recessive allele (f) for no freckles.

Since "F" (freckles) is dominant over "f" (no freckles), all the children (100% represented by Ff) will express the freckled phenotype.

Thus, the probability that their children will have freckles is:

C. 100%