Question

What is the area of a rectangle with a length of 5√3 and a width of 2√3?

Answer 1

To find the area of a rectangle, you can use the formula:

\[
\text{Area} = \text{Length} \times \text{Width}
\]

Given the length \( L = 5\sqrt{3} \) and the width \( W = 2\sqrt{3} \), we can substitute these values into the formula:

\[
\text{Area} = (5\sqrt{3}) \times (2\sqrt{3})
\]

Now, let's compute it step by step:

1. First, multiply the coefficients (the numbers outside the square roots):
\[
5 \times 2 = 10
\]

2. Next, multiply the square root parts:
\[
\sqrt{3} \times \sqrt{3} = \sqrt{3^2} = 3
\]

3. Now, combine the results:
\[
\text{Area} = 10 \times 3 = 30
\]

Therefore, the area of the rectangle is:

\[
\boxed{30}
\]