How much bigger is a the volume of a cone with radius of

12
12 feet and a height of
21
21 feet than a cone with radius of
6
6 feet and a height of
21
21 feet? Use 3.14 for π. Click Here for Help Video

The difference in the volumes of the cones is
cubic feet.

1 answer

To find the difference in volume between the two cones, we first need to calculate the volume of each cone using the formula for the volume of a cone:

\[ V = \frac{1}{3} \pi r^2 h \]

where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.

For the first cone (radius = 12 feet, height = 21 feet):

\[ V_1 = \frac{1}{3} \pi (12)^2 (21) \]

Calculating this step by step:

  1. Calculate \( (12)^2 = 144 \).
  2. Then, calculate \( V_1 = \frac{1}{3} \times 3.14 \times 144 \times 21 \).

Now, calculate \( 144 \times 21 \):

\[ 144 \times 21 = 3024 \]

Now substitute back into the volume formula:

\[ V_1 = \frac{1}{3} \times 3.14 \times 3024 \]

Calculate \( 3.14 \times 3024 \):

\[ 3.14 \times 3024 \approx 9485.76 \]

Now, finally calculate \( V_1 \):

\[ V_1 = \frac{1}{3} \times 9485.76 \approx 3161.92 \text{ cubic feet} \]

For the second cone (radius = 6 feet, height = 21 feet):

\[ V_2 = \frac{1}{3} \pi (6)^2 (21) \]

Following similar steps:

  1. Calculate \( (6)^2 = 36 \).
  2. Calculate \( V_2 = \frac{1}{3} \times 3.14 \times 36 \times 21 \).

Now calculate \( 36 \times 21 \):

\[ 36 \times 21 = 756 \]

Now substitute into the volume formula:

\[ V_2 = \frac{1}{3} \times 3.14 \times 756 \]

Calculate \( 3.14 \times 756 \):

\[ 3.14 \times 756 \approx 2377.44 \]

Now calculate \( V_2 \):

\[ V_2 = \frac{1}{3} \times 2377.44 \approx 792.48 \text{ cubic feet} \]

Now, calculate the difference in volumes:

\[ \text{Difference} = V_1 - V_2 = 3161.92 - 792.48 \approx 2369.44 \text{ cubic feet} \]

Thus, the difference in the volumes of the cones is approximately:

\[ \boxed{2369.44} \text{ cubic feet} \]