Asked by Spirit
how do you find the isoperimetric quotient of an n sided figure?
my side lengths are 5cm
i have split it in to triangles so
360/n
is the central angle
then to work out area of singular triangle its 1/2 base times height
height is something like
tan 180/n =2.5 /height length
please help i get stuck here
The sum of the interior angles is (180)(n-2). So each angle in your triangle is half that, divided by n
angle= 90/n * (n-2)
height= 2.5 tan (90/n (n-2))
Put in n, and you have height.
area for the polygon then is n*area of each triangle, where the area of each triangle is 1/2 bh= 1/2 *5*habove.
I need help to answer this question. (n-2)*180=90
my side lengths are 5cm
i have split it in to triangles so
360/n
is the central angle
then to work out area of singular triangle its 1/2 base times height
height is something like
tan 180/n =2.5 /height length
please help i get stuck here
The sum of the interior angles is (180)(n-2). So each angle in your triangle is half that, divided by n
angle= 90/n * (n-2)
height= 2.5 tan (90/n (n-2))
Put in n, and you have height.
area for the polygon then is n*area of each triangle, where the area of each triangle is 1/2 bh= 1/2 *5*habove.
I need help to answer this question. (n-2)*180=90
Answers
Answered by
Anonymous
If a triangle has a height of 12 in. and a base of 5 in., what is its area?
A. 60 sq. in.
B. 45 sq. in.
C. 30 sq. in.
D. 90 sq. in.
A. 60 sq. in.
B. 45 sq. in.
C. 30 sq. in.
D. 90 sq. in.
Answered by
michelle
A trapezoid has an area of 33.6 square centimeters and a height of 4 centimeters. What is the sum of the base lengths of the trapezoid?
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