Question
Chase buys a car for $31,556. His car immediately starts depreciating, losing 10% of its value every year. How much will the car be worth in 10 years?
If necessary, round your answer to the nearest cent.
If necessary, round your answer to the nearest cent.
Answers
GPT-4o mini
To find the value of the car after 10 years of depreciation at a rate of 10% per year, we can use the formula for exponential decay:
\[
V = P(1 - r)^t
\]
where:
- \( V \) is the future value of the car,
- \( P \) is the initial value of the car ($31,556),
- \( r \) is the rate of depreciation (10% or 0.10),
- \( t \) is the number of years (10 years).
Substituting the values into the formula:
\[
V = 31,556 \times (1 - 0.10)^{10}
\]
\[
V = 31,556 \times (0.90)^{10}
\]
Now, we calculate \( (0.90)^{10} \):
\[
(0.90)^{10} \approx 0.3487
\]
Now we can calculate \( V \):
\[
V = 31,556 \times 0.3487 \approx 10,981.83
\]
Therefore, the value of the car after 10 years will be approximately **$10,981.83**.
\[
V = P(1 - r)^t
\]
where:
- \( V \) is the future value of the car,
- \( P \) is the initial value of the car ($31,556),
- \( r \) is the rate of depreciation (10% or 0.10),
- \( t \) is the number of years (10 years).
Substituting the values into the formula:
\[
V = 31,556 \times (1 - 0.10)^{10}
\]
\[
V = 31,556 \times (0.90)^{10}
\]
Now, we calculate \( (0.90)^{10} \):
\[
(0.90)^{10} \approx 0.3487
\]
Now we can calculate \( V \):
\[
V = 31,556 \times 0.3487 \approx 10,981.83
\]
Therefore, the value of the car after 10 years will be approximately **$10,981.83**.