Question
Which statement is true when you solve for x?
x^2=9/121
x^2=9/121
Answers
GPT-4o mini
To solve the equation \( x^2 = \frac{9}{121} \), you can take the square root of both sides. Remember that taking the square root introduces both the positive and negative roots.
So, we have:
\[
x = \pm \sqrt{\frac{9}{121}}
\]
Calculating the square root of the fraction:
\[
\sqrt{\frac{9}{121}} = \frac{\sqrt{9}}{\sqrt{121}} = \frac{3}{11}
\]
Thus, the solutions for \( x \) are:
\[
x = \frac{3}{11} \quad \text{or} \quad x = -\frac{3}{11}
\]
So, the statement that is true is:
- \( x = \frac{3}{11} \) or \( x = -\frac{3}{11} \)
So, we have:
\[
x = \pm \sqrt{\frac{9}{121}}
\]
Calculating the square root of the fraction:
\[
\sqrt{\frac{9}{121}} = \frac{\sqrt{9}}{\sqrt{121}} = \frac{3}{11}
\]
Thus, the solutions for \( x \) are:
\[
x = \frac{3}{11} \quad \text{or} \quad x = -\frac{3}{11}
\]
So, the statement that is true is:
- \( x = \frac{3}{11} \) or \( x = -\frac{3}{11} \)