Use the image to answer the question.

The total length is 16 inches and width is 10 inches. The length of the removed portion from the bottom right is 12 inches. The shorter portion that is removed has the remaining length of 4 inches. The remaining width after removing the rectangular portion is 6 inches. The shorter portion that is removed has the remaining width of 4 inches.

Nikolai is making an L-shaped platform for his collection of action figures.

What is the surface area of the platform if it is 3 in. thick?

(1 point)
__in.2

1 answer

To calculate the surface area of the L-shaped platform that Nikolai is making, we first need to determine the area of the L-shape.

  1. Dimensions of the entire rectangle:

    • Length = 16 inches
    • Width = 10 inches

    Therefore, the area of the entire rectangle is: \[ \text{Area}_{\text{total}} = \text{Length} \times \text{Width} = 16 , \text{in} \times 10 , \text{in} = 160 , \text{in}^2 \]

  2. Dimensions of the removed portion:

    • Length of the removed portion = 12 inches
    • Width of the removed portion = 4 inches (since the shorter portion has a width of 4 inches)

    Therefore, the area of the removed rectangle is: \[ \text{Area}{\text{removed}} = \text{Length}{\text{removed}} \times \text{Width}_{\text{removed}} = 12 , \text{in} \times 4 , \text{in} = 48 , \text{in}^2 \]

  3. Calculating the area of the L-shape (after removing the rectangle): \[ \text{Area}{\text{L-shape}} = \text{Area}{\text{total}} - \text{Area}_{\text{removed}} = 160 , \text{in}^2 - 48 , \text{in}^2 = 112 , \text{in}^2 \]

  4. Calculating the surface area of the platform (which is 3 inches thick): Since the surface area is technically also influenced by thickness, and assuming we want the area for the sides as well, we typically just consider the surface area of the top face in this case.

However, since the platform is just the top face, we will calculate as follows: \[ \text{Surface Area}{\text{platform}} = \text{Area}{\text{L-shape}} = 112 , \text{in}^2 \]

Thus, the final answer for the surface area of the platform (top face) is: \[ \boxed{112} , \text{in}^2 \]