Question
A Duracell batterie has 7cm and 2cm. What is the volume?
Answers
GPT-4o mini
To calculate the volume of a battery, we typically assume it has a cylindrical shape. The formula for the volume \( V \) of a cylinder is:
\[
V = \pi r^2 h
\]
where \( r \) is the radius, and \( h \) is the height (or length) of the cylinder.
In this case, you provided the following dimensions:
- Height (\( h \)) = 7 cm
- Diameter = 2 cm (which means the radius \( r \) = diameter / 2 = 2 cm / 2 = 1 cm)
Now we can calculate the volume:
1. Calculate the radius:
\[
r = \frac{2 \text{ cm}}{2} = 1 \text{ cm}
\]
2. Plug the values into the volume formula:
\[
V = \pi (1 \text{ cm})^2 (7 \text{ cm}) = \pi (1 \, \text{cm}^2) (7 \text{ cm}) = 7\pi \, \text{cm}^3
\]
3. To get a numerical approximation, use \( \pi \approx 3.14 \):
\[
V \approx 7 \times 3.14 \approx 21.98 \, \text{cm}^3
\]
Therefore, the volume of the Duracell battery is approximately \( 21.98 \, \text{cm}^3 \) or \( 7\pi \, \text{cm}^3 \).
\[
V = \pi r^2 h
\]
where \( r \) is the radius, and \( h \) is the height (or length) of the cylinder.
In this case, you provided the following dimensions:
- Height (\( h \)) = 7 cm
- Diameter = 2 cm (which means the radius \( r \) = diameter / 2 = 2 cm / 2 = 1 cm)
Now we can calculate the volume:
1. Calculate the radius:
\[
r = \frac{2 \text{ cm}}{2} = 1 \text{ cm}
\]
2. Plug the values into the volume formula:
\[
V = \pi (1 \text{ cm})^2 (7 \text{ cm}) = \pi (1 \, \text{cm}^2) (7 \text{ cm}) = 7\pi \, \text{cm}^3
\]
3. To get a numerical approximation, use \( \pi \approx 3.14 \):
\[
V \approx 7 \times 3.14 \approx 21.98 \, \text{cm}^3
\]
Therefore, the volume of the Duracell battery is approximately \( 21.98 \, \text{cm}^3 \) or \( 7\pi \, \text{cm}^3 \).