To find the volume of a cone, you can use the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
Where \( V \) is the volume, \( r \) is the radius of the base, and \( h \) is the height of the cone.
Given:
- \( h = 11 \) units
- \( r = 4 \) units
Now, plug the values into the formula:
\[ V = \frac{1}{3} \pi (4^2) (11) \]
Calculating \( 4^2 \):
\[ 4^2 = 16 \]
Now substituting back into the formula:
\[ V = \frac{1}{3} \pi (16) (11) \]
Now calculating \( 16 \times 11 \):
\[ 16 \times 11 = 176 \]
Now substituting this into the volume formula:
\[ V = \frac{1}{3} \pi (176) \]
Calculating \( \frac{176}{3} \):
\[ \frac{176}{3} \approx 58.67 \]
So now we have:
\[ V \approx 58.67 \pi \]
Using \( \pi \approx 3.14 \) for an approximate numerical answer:
\[ V \approx 58.67 \times 3.14 \approx 183.6 \]
Thus, the approximate volume of the cone is about \( 183.6 \) cubic units.
Final Answer: Approximately \( 183.6 \) cubic units.