Question

Note: Figure is not drawn to scale.

If h = 11 units and r = 4 units, then what is the approximate volume of the cone shown above?
A.

B.

C.

D.

Answer 1

To find the volume of a cone, you can use the formula:

\[
V = \frac{1}{3} \pi r^2 h
\]

Where \( V \) is the volume, \( r \) is the radius of the base, and \( h \) is the height of the cone.

Given:
- \( h = 11 \) units
- \( r = 4 \) units

Now, plug the values into the formula:

\[
V = \frac{1}{3} \pi (4^2) (11)
\]

Calculating \( 4^2 \):

\[
4^2 = 16
\]

Now substituting back into the formula:

\[
V = \frac{1}{3} \pi (16) (11)
\]

Now calculating \( 16 \times 11 \):

\[
16 \times 11 = 176
\]

Now substituting this into the volume formula:

\[
V = \frac{1}{3} \pi (176)
\]

Calculating \( \frac{176}{3} \):

\[
\frac{176}{3} \approx 58.67
\]

So now we have:

\[
V \approx 58.67 \pi
\]

Using \( \pi \approx 3.14 \) for an approximate numerical answer:

\[
V \approx 58.67 \times 3.14 \approx 183.6
\]

Thus, the approximate volume of the cone is about \( 183.6 \) cubic units.

**Final Answer: Approximately \( 183.6 \) cubic units.**