Question
A fruit bowl contains apples, oranges, and bananas. The radius of one of the oranges is 1.4 inches. What is the approximate volume of the orange? Use 3.14 for .
A.
8.21 cubic inches
B.
24.62 cubic inches
C.
1.44 cubic inches
D.
11.49 cubic inches
A.
8.21 cubic inches
B.
24.62 cubic inches
C.
1.44 cubic inches
D.
11.49 cubic inches
Answers
GPT-4o mini
To calculate the volume of a sphere (which is the shape of the orange), we use the formula:
\[
V = \frac{4}{3} \pi r^3
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( \pi \) is approximately 3.14.
Given that the radius of the orange is 1.4 inches, we can substitute this value into the formula:
\[
V = \frac{4}{3} \times 3.14 \times (1.4)^3
\]
First, we calculate \( (1.4)^3 \):
\[
(1.4)^3 = 1.4 \times 1.4 \times 1.4 = 2.744
\]
Now, we can substitute that back into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 2.744
\]
Calculating \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.1867
\]
Now we multiply this by \( 2.744 \):
\[
V \approx 4.1867 \times 2.744 \approx 11.49
\]
Thus, the approximate volume of the orange is \( 11.49 \) cubic inches.
The correct answer is:
**D. 11.49 cubic inches**.
\[
V = \frac{4}{3} \pi r^3
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( \pi \) is approximately 3.14.
Given that the radius of the orange is 1.4 inches, we can substitute this value into the formula:
\[
V = \frac{4}{3} \times 3.14 \times (1.4)^3
\]
First, we calculate \( (1.4)^3 \):
\[
(1.4)^3 = 1.4 \times 1.4 \times 1.4 = 2.744
\]
Now, we can substitute that back into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 2.744
\]
Calculating \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.1867
\]
Now we multiply this by \( 2.744 \):
\[
V \approx 4.1867 \times 2.744 \approx 11.49
\]
Thus, the approximate volume of the orange is \( 11.49 \) cubic inches.
The correct answer is:
**D. 11.49 cubic inches**.