To match the expressions with the values of \( \frac{1}{8} \) and \( 8 \), we can simplify each expression:
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Value = \( \frac{1}{8} \):
- \( 2^{-3} \) is equal to \( \frac{1}{2^3} = \frac{1}{8} \).
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Value = \( 8 \):
- \( 2^{3} \) (since \( 8 = 2^3 \)).
- \( 2^2 \cdot 2 \) can be simplified to \( 2^{2+1} = 2^3 = 8 \).
- \( 2^{8}/2^{5} = 2^{8-5} = 2^{3} = 8\).
- \( 2^{0}/2^{-3} = 2^{0 - (-3)} = 2^{3} = 8 \).
- \( 1/2^7 \cdot 2^{-4} = 2^{-7-4} = 2^{-11} \) does not equal \( 8 \) or \( \frac{1}{8} \) so it is irrelevant.
Now the assignments can be made as follows:
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For \( \frac{1}{8} \): Select \( 2^{-3} \)
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For \( 8 \): Select \( 2^2 \cdot 2 \), \( 2^{8}/2^{5} \), and \( 2^0/2^{-3} \)
So, the final associations are:
- 1/8: \( 2^{-3} \)
- 8: \( 2^2 \cdot 2 \), \( 2^{8}/2^{5} \), \( 2^0/2^{-3} \)
Do not forget to move the corresponding expressions into the correct columns!