Question

What is the average speed, in meters per second, m/s, of a runner who records three different distances over three separate time periods of 30 seconds: 180 meters, 188 meters, and 190 meters?(1 point) Responses 4.1 seconds 4.1 seconds 6.2 m/s 6.2 m/s 18.6 m/s 18.6 m/s 468 m/s

Answer 1

To find the average speed of the runner, we first need to calculate the total distance run and the total time taken.

The distances recorded are:
- First distance: 180 meters
- Second distance: 188 meters
- Third distance: 190 meters

Now, we add these distances together:

\[
180 + 188 + 190 = 558 \text{ meters}
\]

The time for each distance is 30 seconds, and since there are three distances, the total time is:

\[
30 \text{ seconds} \times 3 = 90 \text{ seconds}
\]

Now we can calculate the average speed using the formula:

\[
\text{Average speed} = \frac{\text{Total distance}}{\text{Total time}}
\]

Substituting the values we have:

\[
\text{Average speed} = \frac{558 \text{ m}}{90 \text{ s}} \approx 6.2 \text{ m/s}
\]

Therefore, the average speed of the runner is **6.2 m/s**.