Question

A trapezoid has one pair of opposite parallel sides and one pair of opposite non-parallel the pair of parallel side has lent 15 yd in 19 yards the non parallel sides have length of 11 yd and 8 yards the distance between the parallel sides is 12 yards what is the area of the trapezoid

Answer 1

To find the area of a trapezoid, we can use the formula:

\[
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
\]

where \( b_1 \) and \( b_2 \) are the lengths of the two parallel sides, and \( h \) is the height (the distance between the parallel sides).

In your case:
- One parallel side (base \( b_1 \)) is 15 yards.
- The other parallel side (base \( b_2 \)) is 19 yards.
- The distance between the parallel sides (height \( h \)) is 12 yards.

Now, substitute the values into the area formula:

\[
\text{Area} = \frac{1}{2} \times (15 \, \text{yd} + 19 \, \text{yd}) \times 12 \, \text{yd}
\]

First, calculate the sum of the bases:

\[
15 + 19 = 34 \, \text{yd}
\]

Now, multiply by the height and then divide by 2:

\[
\text{Area} = \frac{1}{2} \times 34 \, \text{yd} \times 12 \, \text{yd}
\]

Calculate \( 34 \times 12 \):

\[
34 \times 12 = 408 \, \text{yd}^2
\]

Now, divide by 2:

\[
\text{Area} = \frac{408}{2} = 204 \, \text{yd}^2
\]

Thus, the area of the trapezoid is:

\[
\text{Area} = 204 \, \text{yd}^2
\]