Question

A jar with 33 g of copper is heated from 240 °Cto 393 °C . How much heat energy was used? (The specific heat capacity for copper is 0.385 Jg°C
0.385

Responses

1.785 J

1944 J

8042 J

13114 J

Answer 1

To calculate the heat energy used, you can use the formula:

\[
Q = m \cdot c \cdot \Delta T
\]

where:
- \( Q \) is the heat energy (in joules),
- \( m \) is the mass (in grams),
- \( c \) is the specific heat capacity (in J/g°C), and
- \( \Delta T \) is the change in temperature (in °C).

Given:
- \( m = 33 \, \text{g} \)
- \( c = 0.385 \, \text{J/g°C} \)
- Initial temperature = 240 °C
- Final temperature = 393 °C

First, calculate the change in temperature:

\[
\Delta T = \text{Final Temperature} - \text{Initial Temperature} = 393 \, °C - 240 \, °C = 153 \, °C
\]

Now, substitute the values into the equation:

\[
Q = 33 \, \text{g} \cdot 0.385 \, \text{J/g°C} \cdot 153 \, °C
\]

Calculating this:

\[
Q = 33 \cdot 0.385 \cdot 153
\]
\[
Q = 33 \cdot 0.385 = 12.705 \, \text{J/}°C
\]
\[
Q = 12.705 \cdot 153 = 1942.065 \, \text{J}
\]

So, the total heat energy used is approximately:

\[
Q \approx 1944 \, \text{J}
\]

Thus, the answer is **1944 J**.