A jar with 33 g of copper is heated from 240 °Cto 393 °C . How much heat energy was used? (The specific heat capacity for copper is 0.385 Jg°C

0.385

Responses

1.785 J

1944 J

8042 J

13114 J

1 answer

To calculate the heat energy used, you can use the formula:

\[ Q = m \cdot c \cdot \Delta T \]

where:

  • \( Q \) is the heat energy (in joules),
  • \( m \) is the mass (in grams),
  • \( c \) is the specific heat capacity (in J/g°C), and
  • \( \Delta T \) is the change in temperature (in °C).

Given:

  • \( m = 33 , \text{g} \)
  • \( c = 0.385 , \text{J/g°C} \)
  • Initial temperature = 240 °C
  • Final temperature = 393 °C

First, calculate the change in temperature:

\[ \Delta T = \text{Final Temperature} - \text{Initial Temperature} = 393 , °C - 240 , °C = 153 , °C \]

Now, substitute the values into the equation:

\[ Q = 33 , \text{g} \cdot 0.385 , \text{J/g°C} \cdot 153 , °C \]

Calculating this:

\[ Q = 33 \cdot 0.385 \cdot 153 \] \[ Q = 33 \cdot 0.385 = 12.705 , \text{J/}°C \] \[ Q = 12.705 \cdot 153 = 1942.065 , \text{J} \]

So, the total heat energy used is approximately:

\[ Q \approx 1944 , \text{J} \]

Thus, the answer is 1944 J.