Question

A cubic foot of water is about 7.48 gallons. How many gallons of water would be needed to fill the rectangular pool to 91% capacity?
The pool will require _______ gallons of water (Round to the tenths place)
Height: 5
Width: 8
Length: 28

Answers

GPT-4o mini
To determine how many gallons of water would be needed to fill the pool to 91% capacity, we will first calculate the volume of the pool in cubic feet, and then convert that volume to gallons.

1. **Calculate the volume of the pool in cubic feet**:

\[
\text{Volume} = \text{Height} \times \text{Width} \times \text{Length}
\]

\[
\text{Volume} = 5 \, \text{ft} \times 8 \, \text{ft} \times 28 \, \text{ft} = 1120 \, \text{cubic feet}
\]

2. **Calculate 91% of the volume**:

\[
91\% \text{ of volume} = 0.91 \times 1120 \, \text{cubic feet} = 1019.2 \, \text{cubic feet}
\]

3. **Convert cubic feet to gallons** (using the conversion factor that 1 cubic foot = 7.48 gallons):

\[
\text{Gallons} = 1019.2 \, \text{cubic feet} \times 7.48 \, \text{gallons/cubic foot}
\]

\[
\text{Gallons} \approx 7615.536 \, \text{gallons}
\]

4. **Round to the tenths place**:

The final result rounded to the tenths place is:

\[
\text{Gallons} \approx 7615.5 \, \text{gallons}
\]

Therefore, the pool will require **7615.5 gallons** of water to fill it to 91% capacity.