Question
Problem 2
Select the number line that represents 3·(−6) .
You can think of 3·(−6) as 3 groups of −6.
Number line showing 3 arrows back to back pointing left. The first arrow starts at 0. Each arrow has a value of negative 6.
Number line showing 3 arrows back to back pointing right. The first arrow starts at 0. Each arrow has a value of 6.
Select the number line that represents 3·(−6) .
You can think of 3·(−6) as 3 groups of −6.
Number line showing 3 arrows back to back pointing left. The first arrow starts at 0. Each arrow has a value of negative 6.
Number line showing 3 arrows back to back pointing right. The first arrow starts at 0. Each arrow has a value of 6.
Answers
GPT-4o mini
To represent the expression \(3 \cdot (-6)\) on a number line, we need to understand that this expression indicates \(3\) groups of \(-6\).
When visualizing this on a number line:
- The value \(-6\) is found to the left of \(0\), as it is a negative number.
- Multiplying by \(3\) means we will move \(3\) times the distance of \(-6\) to the left.
Therefore, if we start at \(0\) and move \(6\) units to the left three times, we would mark the point on the number line that represents the value of \(3 \cdot (-6)\), which is \(-18\).
Thus, the number line that correctly represents \(3 \cdot (-6)\) is:
**Number line showing 3 arrows back to back pointing left. The first arrow starts at 0. Each arrow has a value of -6.**
This shows that you move \(6\) units to the left a total of \(3\) times, leading to the final point at \(-18\).
When visualizing this on a number line:
- The value \(-6\) is found to the left of \(0\), as it is a negative number.
- Multiplying by \(3\) means we will move \(3\) times the distance of \(-6\) to the left.
Therefore, if we start at \(0\) and move \(6\) units to the left three times, we would mark the point on the number line that represents the value of \(3 \cdot (-6)\), which is \(-18\).
Thus, the number line that correctly represents \(3 \cdot (-6)\) is:
**Number line showing 3 arrows back to back pointing left. The first arrow starts at 0. Each arrow has a value of -6.**
This shows that you move \(6\) units to the left a total of \(3\) times, leading to the final point at \(-18\).