To calculate the volume of the can using the formula \( V = \pi \cdot r^2 \cdot h \), we need to substitute the values for \( \pi \), \( r \), and \( h \).
Given:
- \( r = 3 \) inches
- \( h = 5 \) inches
- \( \pi \approx 3.14 \)
Now, let's calculate the volume:
\[ V = \pi \cdot r^2 \cdot h \]
\[ V = 3.14 \cdot (3^2) \cdot 5 \]
Calculating \( 3^2 \):
\[ 3^2 = 9 \]
Now substituting that into the volume formula:
\[ V = 3.14 \cdot 9 \cdot 5 \]
Calculating \( 9 \cdot 5 \):
\[ 9 \cdot 5 = 45 \]
Now substituting this back in:
\[ V = 3.14 \cdot 45 \]
Calculating \( 3.14 \cdot 45 \):
\[ V = 141.3 \]
Thus, the volume of the can is:
\[ \boxed{141.3 , \text{in}^3} \]