Question

Graph the equation I - y = 6 using the form y = ma + b. (1 point)
given
graft 1 (0, 0) (6, 6)
graft 2 (1,-10)
graft 3 (0,-6) (1,-5)
graft 4 (0,3) (3,2)

Answer 1

To graph the equation \( I - y = 6 \), we first need to rearrange it into the slope-intercept form (y = mx + b).

Starting with the equation:
\[ I - y = 6 \]

We can solve for \( y \):
\[ y = I - 6 \]

This matches the form \( y = mx + b \) where:
- \( m = 1 \) (the slope)
- \( b = -6 \) (the y-intercept)

Now we can identify the key points to graph this line:
1. The y-intercept occurs at (0, -6).
2. The slope of 1 means that for every 1 unit you move up in \( y \), you move 1 unit to the right in \( x \).

From the y-intercept (0, -6), you can find other points:
- From (0, -6), moving up 1 unit and to the right 1 unit gives the point (1, -5).
- Continuing this pattern, you can find other points (2, -4), (3, -3), etc.

Now, looking at the provided graphs:

- **Graft 1** (0, 0) (6, 6): This represents the line crossing through (0,0) and (6,6), which does not match our equation.
- **Graft 2** (1, -10): This point does not lie on the line defined by the equation.
- **Graft 3** (0, -6) (1, -5): This correctly represents points on the line we derived.
- **Graft 4** (0, 3) (3, 2): This does not match our equation either.

The correct graph for the equation \( y = I - 6 \) is **Graft 3**, which includes the points \( (0, -6) \) and \( (1, -5) \).