Graph the equation I - y = 6 using the form y = ma + b. (1 point)

given
graft 1 (0, 0) (6, 6)
graft 2 (1,-10)
graft 3 (0,-6) (1,-5)
graft 4 (0,3) (3,2)

1 answer

To graph the equation \( I - y = 6 \), we first need to rearrange it into the slope-intercept form (y = mx + b).

Starting with the equation: \[ I - y = 6 \]

We can solve for \( y \): \[ y = I - 6 \]

This matches the form \( y = mx + b \) where:

  • \( m = 1 \) (the slope)
  • \( b = -6 \) (the y-intercept)

Now we can identify the key points to graph this line:

  1. The y-intercept occurs at (0, -6).
  2. The slope of 1 means that for every 1 unit you move up in \( y \), you move 1 unit to the right in \( x \).

From the y-intercept (0, -6), you can find other points:

  • From (0, -6), moving up 1 unit and to the right 1 unit gives the point (1, -5).
  • Continuing this pattern, you can find other points (2, -4), (3, -3), etc.

Now, looking at the provided graphs:

  • Graft 1 (0, 0) (6, 6): This represents the line crossing through (0,0) and (6,6), which does not match our equation.
  • Graft 2 (1, -10): This point does not lie on the line defined by the equation.
  • Graft 3 (0, -6) (1, -5): This correctly represents points on the line we derived.
  • Graft 4 (0, 3) (3, 2): This does not match our equation either.

The correct graph for the equation \( y = I - 6 \) is Graft 3, which includes the points \( (0, -6) \) and \( (1, -5) \).