Question
Which chemical equation below shows a balanced reaction that follows the law of conservation of matter?(1 point)
Responses
2H2 + 2O2 → 2H2O
2H 2 + 2O 2 → 2H 2 O
H2 + O2 → H2O
H 2 + O 2 → H 2 O
H2 + O2 → 2H2O
H 2 + O 2 → 2H 2 O
2H2 +O2 → 2H2O
Responses
2H2 + 2O2 → 2H2O
2H 2 + 2O 2 → 2H 2 O
H2 + O2 → H2O
H 2 + O 2 → H 2 O
H2 + O2 → 2H2O
H 2 + O 2 → 2H 2 O
2H2 +O2 → 2H2O
Answers
GPT-4o mini
To determine which chemical equation shows a balanced reaction that follows the law of conservation of matter, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
Let's analyze each option:
1. **2H2 + 2O2 → 2H2O**
- Left: 4 H atoms, 4 O atoms
- Right: 4 H atoms, 2 O atoms
- **Not balanced (4 O on the left vs. 2 O on the right)**
2. **H2 + O2 → H2O**
- Left: 2 H atoms, 2 O atoms
- Right: 2 H atoms, 1 O atom
- **Not balanced (2 O on the left vs. 1 O on the right)**
3. **H2 + O2 → 2H2O**
- Left: 2 H atoms, 2 O atoms
- Right: 4 H atoms, 2 O atoms
- **Not balanced (2 H on the left vs. 4 H on the right)**
4. **2H2 + O2 → 2H2O**
- Left: 4 H atoms, 2 O atoms
- Right: 4 H atoms, 2 O atoms
- **Balanced (4 H on the left = 4 H on the right, and 2 O on the left = 2 O on the right)**
So, the correct balanced equation that follows the law of conservation of matter is **2H2 + O2 → 2H2O**.
Let's analyze each option:
1. **2H2 + 2O2 → 2H2O**
- Left: 4 H atoms, 4 O atoms
- Right: 4 H atoms, 2 O atoms
- **Not balanced (4 O on the left vs. 2 O on the right)**
2. **H2 + O2 → H2O**
- Left: 2 H atoms, 2 O atoms
- Right: 2 H atoms, 1 O atom
- **Not balanced (2 O on the left vs. 1 O on the right)**
3. **H2 + O2 → 2H2O**
- Left: 2 H atoms, 2 O atoms
- Right: 4 H atoms, 2 O atoms
- **Not balanced (2 H on the left vs. 4 H on the right)**
4. **2H2 + O2 → 2H2O**
- Left: 4 H atoms, 2 O atoms
- Right: 4 H atoms, 2 O atoms
- **Balanced (4 H on the left = 4 H on the right, and 2 O on the left = 2 O on the right)**
So, the correct balanced equation that follows the law of conservation of matter is **2H2 + O2 → 2H2O**.