To solve the inequality \( 4x - 8 \leq 4 \), we can start by isolating \( x \):
-
Add 8 to both sides: \[ 4x - 8 + 8 \leq 4 + 8 \] \[ 4x \leq 12 \]
-
Divide both sides by 4: \[ x \leq 3 \]
Now we need to find the whole numbers less than 10 that satisfy \( x \leq 3 \). The whole numbers less than or equal to 3 are \( 0, 1, 2, \) and \( 3 \).
Therefore, the solutions are:
0, 1, 2, 3