Question

Liam has a bag that contains pineapple chews, cherry chews, and lime chews. He performs an experiment. Liam randomly removes a chew from the bag, records the result, and returns the chew to the bag. Liam performs the experiment 62 times. The results are shown below:
A pineapple chew was selected 58 times.
A cherry chew was selected 2 times.
A lime chew was selected 2 times.

Based on these results, express the probability that the next chew Liam removes from the bag will be cherry chew as a decimal to the nearest hundredth

Answer 1

To find the probability that the next chew Liam removes from the bag will be a cherry chew, we can use the frequency of each type of chew selection observed during the experiment.

From the results:
- Pineapple chews were selected 58 times.
- Cherry chews were selected 2 times.
- Lime chews were selected 2 times.

First, we find the total number of selections made, which is given as 62.

The probability \( P \) of selecting a cherry chew is calculated as follows:

\[
P(\text{cherry}) = \frac{\text{Number of cherry chews selected}}{\text{Total selections}} = \frac{2}{62}
\]

Calculating this gives:

\[
P(\text{cherry}) = \frac{2}{62} = \frac{1}{31} \approx 0.0322580645
\]

Now we round this probability to the nearest hundredth:

\[
0.0322580645 \approx 0.03
\]

Thus, the probability that the next chew Liam removes from the bag will be a cherry chew is

\[
\boxed{0.03}.
\]