Question
Use the table to answer the question.
Size
Color Large Medium Small TOTAL
Yellow 2 4 11 17
Blue 1 1 4 6
Red 1 2 4 7
TOTAL 4 7 19 30
What is P(blue or medium)
?
(1 point)
Responses
1030
Start Fraction 10 over 30 End Fraction
1230
Start Fraction 12 over 30 End Fraction
1330
Start Fraction 13 over 30 End Fraction
630
Size
Color Large Medium Small TOTAL
Yellow 2 4 11 17
Blue 1 1 4 6
Red 1 2 4 7
TOTAL 4 7 19 30
What is P(blue or medium)
?
(1 point)
Responses
1030
Start Fraction 10 over 30 End Fraction
1230
Start Fraction 12 over 30 End Fraction
1330
Start Fraction 13 over 30 End Fraction
630
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find \( P(\text{blue or medium}) \), we need to use the formula for the probability of the union of two events:
\[
P(A \cup B) = P(A) + P(B) - P(A \cap B)
\]
Where:
- \( A \) is the event of selecting a blue item,
- \( B \) is the event of selecting a medium item.
**Step 1: Calculate \( P(A) \)**
The total number of blue items is 6, as seen in the table. Therefore:
\[
P(\text{blue}) = \frac{6}{30}
\]
**Step 2: Calculate \( P(B) \)**
To find the total number of medium items, we can add all medium items across colors (which is 7):
\[
P(\text{medium}) = \frac{7}{30}
\]
**Step 3: Calculate \( P(A \cap B) \)**
Now we need to find the number of items that are both blue and medium. From the table, there is 1 blue medium item:
\[
P(\text{blue and medium}) = \frac{1}{30}
\]
**Step 4: Apply the formula**
Now we can substitute these probabilities into our union formula:
\[
P(\text{blue or medium}) = P(\text{blue}) + P(\text{medium}) - P(\text{blue and medium})
\]
\[
P(\text{blue or medium}) = \frac{6}{30} + \frac{7}{30} - \frac{1}{30}
\]
\[
P(\text{blue or medium}) = \frac{6 + 7 - 1}{30} = \frac{12}{30}
\]
Thus,
\[
P(\text{blue or medium}) = \frac{12}{30}
\]
So the correct response is:
\[
\frac{12}{30}
\]
This corresponds to:
**Response: \( \frac{12}{30} \)**
\[
P(A \cup B) = P(A) + P(B) - P(A \cap B)
\]
Where:
- \( A \) is the event of selecting a blue item,
- \( B \) is the event of selecting a medium item.
**Step 1: Calculate \( P(A) \)**
The total number of blue items is 6, as seen in the table. Therefore:
\[
P(\text{blue}) = \frac{6}{30}
\]
**Step 2: Calculate \( P(B) \)**
To find the total number of medium items, we can add all medium items across colors (which is 7):
\[
P(\text{medium}) = \frac{7}{30}
\]
**Step 3: Calculate \( P(A \cap B) \)**
Now we need to find the number of items that are both blue and medium. From the table, there is 1 blue medium item:
\[
P(\text{blue and medium}) = \frac{1}{30}
\]
**Step 4: Apply the formula**
Now we can substitute these probabilities into our union formula:
\[
P(\text{blue or medium}) = P(\text{blue}) + P(\text{medium}) - P(\text{blue and medium})
\]
\[
P(\text{blue or medium}) = \frac{6}{30} + \frac{7}{30} - \frac{1}{30}
\]
\[
P(\text{blue or medium}) = \frac{6 + 7 - 1}{30} = \frac{12}{30}
\]
Thus,
\[
P(\text{blue or medium}) = \frac{12}{30}
\]
So the correct response is:
\[
\frac{12}{30}
\]
This corresponds to:
**Response: \( \frac{12}{30} \)**
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.