Question
Use the provided information and the information about Mongolian gerbils from your eBook to correctly match the frequency of alleles.
Frequency of the A allele =
number of A alleles in population total number of alleles in population
There is a Mongolian gerbil population with the alleles of A of a. The population being studied has a total number of 224 A alleles and a total number of 176 a
alleles.
A population of 200 Mongolian gerbils living near Russia's Lake Baikal includes 80 brown gerbils with the AA genotype, 64 brown gerbils with the Aa genotype, and 56 black gerbils with the aa genotype. Use this information to complete the table.
Genotype
Number of individuals
Number of A alleles
AA
80
160
Aa
64
64
56
Number of a alleles
64
56
What is the total number of alleles?
What is the frequency of the A allele?
What is the frequency of the a allele?
[ Choose ]
[ Choose ]
[ Choose]
0.56
0.44
400
Frequency of the A allele =
number of A alleles in population total number of alleles in population
There is a Mongolian gerbil population with the alleles of A of a. The population being studied has a total number of 224 A alleles and a total number of 176 a
alleles.
A population of 200 Mongolian gerbils living near Russia's Lake Baikal includes 80 brown gerbils with the AA genotype, 64 brown gerbils with the Aa genotype, and 56 black gerbils with the aa genotype. Use this information to complete the table.
Genotype
Number of individuals
Number of A alleles
AA
80
160
Aa
64
64
56
Number of a alleles
64
56
What is the total number of alleles?
What is the frequency of the A allele?
What is the frequency of the a allele?
[ Choose ]
[ Choose ]
[ Choose]
0.56
0.44
400
Answers
GPT-4o mini
To answer the questions about the frequency of alleles in the Mongolian gerbil population, we first need to calculate the total number of alleles and the frequencies of each allele.
### Step 1: Calculate the Total Number of Alleles
Each individual has 2 alleles. Therefore, for a population of 200 Mongolian gerbils:
\[
\text{Total number of alleles} = \text{Number of individuals} \times 2 = 200 \times 2 = 400
\]
### Step 2: Count the Number of A and a Alleles
We know the following about the genotypes:
- **AA**: 80 individuals contribute 2 A alleles each = \(80 \times 2 = 160\) A alleles
- **Aa**: 64 individuals contribute 1 A allele each = \(64 \times 1 = 64\) A alleles
- **aa**: 56 individuals contribute 0 A alleles = \(56 \times 0 = 0\) A alleles
Now, we can sum the A alleles:
\[
\text{Total A alleles} = 160 + 64 + 0 = 224
\]
Next, we need to calculate the number of `a` alleles:
- **AA**: contributes 0 a alleles = \(80 \times 0 = 0\)
- **Aa**: contributes 1 a allele each = \(64 \times 1 = 64\) a alleles
- **aa**: contributes 2 a alleles each = \(56 \times 2 = 112\) a alleles
Now, we can sum the a alleles:
\[
\text{Total a alleles} = 0 + 64 + 112 = 176
\]
### Step 3: Calculate Frequencies of Each Allele
The frequency of an allele can be calculated using the formula:
\[
\text{Frequency of allele} = \frac{\text{Number of that allele in the population}}{\text{Total number of alleles in the population}}
\]
**Frequency of A allele**:
\[
\text{Frequency of A} = \frac{224}{400} = 0.56
\]
**Frequency of a allele**:
\[
\text{Frequency of a} = \frac{176}{400} = 0.44
\]
### Summary
- Total number of alleles = **400**
- Frequency of the A allele = **0.56**
- Frequency of the a allele = **0.44**
Thus, the final answers for filling in the table will be as follows:
- Total number of alleles: 400
- Frequency of A allele: 0.56
- Frequency of a allele: 0.44
### Step 1: Calculate the Total Number of Alleles
Each individual has 2 alleles. Therefore, for a population of 200 Mongolian gerbils:
\[
\text{Total number of alleles} = \text{Number of individuals} \times 2 = 200 \times 2 = 400
\]
### Step 2: Count the Number of A and a Alleles
We know the following about the genotypes:
- **AA**: 80 individuals contribute 2 A alleles each = \(80 \times 2 = 160\) A alleles
- **Aa**: 64 individuals contribute 1 A allele each = \(64 \times 1 = 64\) A alleles
- **aa**: 56 individuals contribute 0 A alleles = \(56 \times 0 = 0\) A alleles
Now, we can sum the A alleles:
\[
\text{Total A alleles} = 160 + 64 + 0 = 224
\]
Next, we need to calculate the number of `a` alleles:
- **AA**: contributes 0 a alleles = \(80 \times 0 = 0\)
- **Aa**: contributes 1 a allele each = \(64 \times 1 = 64\) a alleles
- **aa**: contributes 2 a alleles each = \(56 \times 2 = 112\) a alleles
Now, we can sum the a alleles:
\[
\text{Total a alleles} = 0 + 64 + 112 = 176
\]
### Step 3: Calculate Frequencies of Each Allele
The frequency of an allele can be calculated using the formula:
\[
\text{Frequency of allele} = \frac{\text{Number of that allele in the population}}{\text{Total number of alleles in the population}}
\]
**Frequency of A allele**:
\[
\text{Frequency of A} = \frac{224}{400} = 0.56
\]
**Frequency of a allele**:
\[
\text{Frequency of a} = \frac{176}{400} = 0.44
\]
### Summary
- Total number of alleles = **400**
- Frequency of the A allele = **0.56**
- Frequency of the a allele = **0.44**
Thus, the final answers for filling in the table will be as follows:
- Total number of alleles: 400
- Frequency of A allele: 0.56
- Frequency of a allele: 0.44